Q. 94.0( 60 Votes )

Vapour pressure o

Answer :

Given,


Vapour pressure of water, PIo = 23.8 mm of Hg


Weight of water, w1 = 850 g


Weight of urea, w2 = 50 g


Molecular weight of water, M1 = 18 g/mol


Molecular weight of urea, M2 = 60 g/mol


n1 = = 47.22 mol


n2 = = 0.83 mol


We have to calculate vapour pressure of water in the solution p1


By using Rault's therom,




(relative lowering)


PI = 23.4 mm of Hg


Hence,


The vapour pressure of water in the solution is 23.4mm of Hg and its relative lowering is 0.0173.


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