Answer :
(i) True, A ∩ B = φ
(ii) True, A ∪ B = S and A ∩ B = φ
(iii) True, B' = S - B = A.
(iv) False, A ∩ C = {(2, 1), (2, 2), (2, 3), (4, 1)} ≠ φ .
(v) True, A' = B and B' = A ⇒ A' ∩ B' = B ∩ A = φ.
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