Q. 19

Using Valence Bon

Answer :

(a) [CoF6]3-:- The atomic number of Co is 27 and its valence shell electronic configuration is 3d74s2.
Co is in +3 oxidation state in the complex [CoF6] 3- . In this state, there are 6 electrons in the 3d orbitals and 4s, 4p and 4d orbitals are vacant.
As F- is a weak field ligand, so it is unable to pair up the electrons of the 3d orbitals. Hence, six equivalent hybrid orbitals are formed by one 4s, three 4p and two 4d orbitals and the complex is sp3d2 hybridized and it is octahedral in shape.


Moreover, it has 4 unpaired electrons in the 3d orbital. So it is paramagnetic in nature.
b) [Ni(CN)4]2-:- The atomic number of Ni is 28 and its valence shell electronic configuration is 3d84s2.
Ni is in +2 oxidation state in the complex [Ni(CN)4] 2-. In this state, there are 8 electrons in the 3d orbital and 4s, 4p and 4d orbitals are vacant.


As CN- is a strong field ligand, so it pair up the two unpaired electrons of the 3d orbital. So four 3d orbitals become doubly occupied and one 3d orbital remains vacant.
Hence, four equivalent hybrid orbitals are formed by one 3d, one 4s and two 4p orbitals and the complex is dsp2 hybridized and it is square planar in shape.


Moreover, it has no unpaired electron in it. So it is diamagnetic in nature.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses