Using second law of motion, derive the relation between force and acceleration. A bullet of 10 g strikes a sand-bag at a speed of 103 ms-1 and gets embedded after travelling 5 cm. Calculate:(i) The resistive force exerted by the sand on the bullet(ii) The time taken by the bullet to come to rest.

(i) Given,

m = 10g = kg

u = 103 m/s

v = 0, s = 5cm = m

v2 – u2 = 2as

0 – (103)2 = 2 × a ×

-(103) × (10)3 =

a = (-1000 × ) × 100

= -107 ms-2

F = ma

= 1/100x - 107

= -105 N

(ii) v = u +at

0 = (103) – 107 × t

t =

t = 10-4s

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