Answer :

Given:


Wavelength of light, λ = 2271 Å = 2271 × 10-10m


Power of mercury source, E = 100 Js-1


Stopping potential, Vs = -1.3 V


Let frequency of light = v


Work function, Φ0 is given by,


Φ0 = hv-eVs


Φ0 =


Where,


h = Planck’s constant = 6.6 × 10-34Js


c = speed of light = 3 × 108m


λ = wavelength of light


e = charge on each electron = 1.6 × 10-19C


Φ0 =


Φ0 = 6.64 × 10-19J


Φ0 = (6.64/1.6) × 10-19 eV = 4.15 eV


Let v0 be the threshold frequency of the metal,


Φ0 = hv0


v0 = Φ0/h


v0 = 6.6 × 10-19/ 6.6 × 10-34


v0 = 1.00. × 10-15 s-1


Wavelength of red light, λ’ = 6323 × 10-10m


Frequency of red light can be given as,


v' = c/λ’


v’ =


v’ = 4.74 × 1014 Hz


Since the threshold frequency is greater than the frequency of red light, the photocell will not respond to the red light produced.


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