Q. 1

Two tailors, A an

Answer :

Let A works for x days and B works for y days.

x ≥ 0, y ≥ 0


Minimum no. of shirts = 60

Given: A can stitch 6 shirts and 4 pairs of trousers while B can stitch 10 shirts and 4 pairs of trousers


6x + 10y ≥ 60


3x + 5y ≥ 30


Minimum no. of trousers = 32


4x + 4y ≥ 32


x + y ≥ 8


Let z be the total labor cost.


z = 300x + 400 y


the given L.P problem reduces to: z = 300x + 400y


x ≥ 0, y ≥ 0, 3x + 5y ≥ 30, x + y ≥ 8

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