Answer :

Now here the metal strips are riveted together so the stress in the rivet would be shearing stress since force would be perpendicular to surface area of rivet and stress is the restoring force per unit area, restoring force is same as applied force in equilibrium condition, the rivet joints and force on them are as shown in the figure



Now we know shearing stress is given as


๐ˆs = F/A


Where ๐ˆs is the shearing stress F is the Shearing Force and A is the surface area


So, we get maximum force that can be applied to a rivet as


F = ๐ˆs/A


There are four rivets and We are given diameter of each rivet as d = 6.0 mm


So, radius of each rivet is


r = d/2 = 6.0mm/2 = 3.0 mm


or r = 3 ร— 10-3m


since rivet is circular in shape area is given as


A = ฯ€r2


So, area of each rivet is


A = ฯ€ ร— 3 ร— 10-3mร—3 ร— 10-3m = 28.27 ร— 10-6 m2


So, area of each rivet is


A = 2.827 ร— 10-5m2


Now we know shearing stress is given as


๐ˆs = F/A


Where ๐ˆs is the shearing stress F is the Shearing Force and A is the surface area


So, we get maximum force that can be applied to a rivet as


F = ๐ˆs ร— A


We are given maximum shearing stress that can be applied to a rivet as


๐ˆs = 6.9 ร— 107 Pa


Putting value of ๐ˆs and A we get maximum shearing force each rivet can with stand as


F = 6.9 ร— 107Nm-2 ร— 2.827 ร— 10-5m2 = 19.50 ร— 102 N


So each rivet can withstand a force of


F = 1.95 ร— 103 N = 1.95 KN


Now each rivet is to carry one-quarter of the load i.e 1/4 th of the total load so total load that can be applied or maximum tension that can be exerted is four timed of that can be applied on each rivet i.e. the maximum tension


Tmax = 4 ร— F


So Tmax = 4 ร— 1.95 KN = 78 KN


So, the maximum tension that can be exerted by riveted strip is 78 ร—103 N or 78 KN


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