# Two sitar s

Given,

Frequency of string A, fA = 324 Hz

Let the frequency of string B be fB.

Beat’s frequency, n = 6 Hz

Beat's Frequency is given as:

n=|fAfB|

6 = 324 fB

fB = 318 Hz or 330 Hz

Frequency decreases with a decrease in the tension in a string because frequency is directly proportional to the square root of tension as f T

Hence, the beat frequency cannot be 330 Hz.

So, fB = 318 Hz

NOTE: A beat is an interference pattern between two sounds of slightly different frequencies, perceived as a periodic variation in volume whose rate is the difference of the two frequencies.

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