Q. 63.9( 31 Votes )

Two samples ‘m’ and ‘n’ of slaked lime were obtained from two different reactions. The details about their composition are as follows:

‘sample m’ mass: 7g

Mass of constituent oxygen: 2g

Mass of constituent calcium: 5g

‘sample n’ mass: 1.4g

Mass of constituent oxygen: 0.4g

Mass of constituent calcium: 1.0g

Which law of chemical combination does this prove? Explain.

Answer :

Slaked lime = calcium hydroxide {Ca(OH)2}

The law of constant proportions states that “The proportion by weight of the constituent elements in the various samples of a compound is fixed,”

The proportion by weight of oxygen and calcium in slaked lime(in sample m) is 2:5 i.e. 0.4:1

The proportion by weight of oxygen and calcium in slaked lime(in sample n) is 0.4:1.0

Since the proportions of constituent elements remain fixed it follows the law of constant proportion.

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