Two resistors, wi

Given: R₁ = 5Ω

R₂ = 10Ω

EMF = 6V

i) To obtain minimum current, we should connect the two resistors in series. To obtain maximum current, we should connect the two resistors in parallel.

ii) Calculation of strength of the total current in both the cases:

I case: Resistors in series

When several resistors are joined in series, then the total resistance (R_s) is equal to:

R_s = R₁ + R₂

• R_s = 5Ω + 10Ω = 15Ω

To calculate the flowing current (I), apply the Ohm’s law:

V = IR

•

• I = 0.4A

Thus, by connecting the resistors in series, the minimum current flowing is 0.4A.

II case: Resistors in parallel

When several resistors are joined in series, then the total resistance (R_P) is equal to:

•

•

•

To calculate the flowing current (I), apply the Ohm’s law:

V = IR

•

• I = 1.8A

Thus, by connecting the resistors in parallel, the maximum current flowing is 1.8A.