Q. 104.0( 2 Votes )

# Two particles A<s A. their momenta are the same.

B. their energies are the same.

C. energy of A_{1} is less than the energy of A_{2}.

D. energy of A_{1} is more than the energy of A_{2}.

Answer :

We know the de Broglie wavelength of a particle is given by,

where h is the Planck’s constant, m is the mass and v is the velocity

where p=mv.

Since h is a constant and the particles have the same de Broglie wavelengths, their momenta are the same.

The kinetic energy of a particle with de Broglie wavelength is given by,

Hence, their energies are different.

m_{1} > m_{2}

Hence, K_{2} > K_{1}

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

Consider a 20 W bPhysics - Exemplar

A neutron beam ofPhysics - Exemplar

A particle A withPhysics - Exemplar

The de Broglie waPhysics - Exemplar

Two particles A<sPhysics - Exemplar

(i) In the explanPhysics - Exemplar

A proton and an αPhysics - Exemplar

Show that it is nHC Verma - Concepts of Physics Part 2