Q. 304.7( 3 Votes )

# Two narrow bores

Answer :

Diameter of the first tube = 3 mm

Diameter of the second tube = 6 mm

Thus, Radius of the first tube, r1 = 1.5 mm = 1.5 × 10-3 m

Radius of the first tube, r2 = 3 mm = 3 × 10-3 m

Surface tension of water, S = 7.3 × 10-2 N/m

Density of water, ρ = 1000 kg/m3

Angle of contact between bore surface and water, θ = 00

Acceleration due to gravity, g = 9.8 m/s

Height of water rise, Where,

S = Surface tension

θ = Contact angle

ρ = Density

g = acceleration due to gravity

r = radius

Let h1 and h2 be the height rise of water in tube1 and tube2 respectively. Then the height are given by, ; Thus, the difference between heights is given by,

Δh = h1 – h2    = 4.996 × 10-3 m

≈ 4.97 mm

The difference between the water levels in two bores = 4.97 mm

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