# Two masses Given:

m= 8 kg

M= 12 kg

g(acceleration due to gravity)=10 m/ s2

The system of masses and pulley has one smaller mass,’m’ and one larger mass, ‘M’.

‘T’ is the tension in the strings,

‘a’ is the acceleration of the masses.

The larger mass, ‘M’ moves downward with supposed acceleration ‘a’ and thus mass, ‘m’ moves upward.

According to the Newton’s second law of motion, we get equation of motion for each masses,

For mass m:

T – mg = ma …..(i)

For mass M:

Mg - T = Ma ……(ii)

We add both of the equation(i) and (ii), to get:

(M – m)g = (M+m)a ……(iii)

putting = 2 m/s2

The acceleration of the masses is 2 m/s2

To find tension, We substitute the value of a from eq(iii) in eq(ii), we get:   T=96 N

The tension in the string when the masses are released is 96 N.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

A rectangular boxPhysics - Exemplar

A helicopter of mPhysics - Exemplar

There are four foPhysics - Exemplar

When a body <spanPhysics - Exemplar

Block <span lang=Physics - Exemplar

A block <span lanPhysics - Exemplar

Two <span lang="EPhysics - Exemplar