Answer :

According, to the above given diagram wire with current I1 is in +ve x-axis and wire with current I �2 is in +ve y-axis. Now, according to Biot-savart law and right-hand thumb rule magnetic field due I1 current at O2 is given by where,


μo is magnetic permeability in vacuum,


is magnetic field vector,


I1 is current flowing in 1st wire,


and is the displacement vector for point we want to calculate the magnetic field.


And will be in -ve y-axis direction, which means and for wire carrying I2 current will be parallel to each other. And force on current carrying straight wire due to uniform magnetic field is given by


F= I2 × where,


B is magnetic field strength;


I2 is current in the wire;


is length vector of wire in direction of current.


So, since angle between and is 0o so, F is also 0.


Hence, force on wire carrying current I2 due to magnetic field of wire carrying current I1 is zero (0).


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