Answer :

According, to the above given diagram wire with current I_{1} is in +ve x-axis and wire with current I �_{2} is in +ve y-axis. Now, according to Biot-savart law and right-hand thumb rule magnetic field due I_{1} current at O_{2} is given by where,

μ_{o} is magnetic permeability in vacuum,

is magnetic field vector,

I_{1} is current flowing in 1^{st} wire,

and is the displacement vector for point we want to calculate the magnetic field.

And will be in -ve y-axis direction, which means and for wire carrying I_{2} current will be parallel to each other. And force on current carrying straight wire due to uniform magnetic field is given by

F= I_{2} × where,

B is magnetic field strength;

I_{2} is current in the wire;

is length vector of wire in direction of current.

So, since angle between and is 0^{o} so, F is also 0.

Hence, force on wire carrying current I_{2} due to magnetic field of wire carrying current I_{1} is zero (0).

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