Answer :

Given:

Distance between centres of spheres, r = 50 cm = .5m

Charge on each sphere, q = 6.5 × 10^{-7} C

Mutual force of electrostatic repulsion

…(1)

Where, F= mutual force of attraction

q_{1} = charge on sphere 1

q_{2} = charge on sphere 2

r = distance between centres

Where, ε_{0} is the permittivity of the free space.

Now, putting the values of q_{1}, q_{2} and r in equation (1).

⇒ F = 1.52 × 10^{-2} N

Hence the mutual force between two spheres is 1.52 × 10^{-2}N. Since the sign is positive so the force is repulsive in nature.

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

(a) Describe briePhysics - Board Papers

Repeat the previoHC Verma - Concepts of Physics Part 2

There is another Physics - Exemplar

Does the charge gPhysics - Board Papers