Answer :

Given


Initial temperature of gas in both bulbs T1 =0


Initial pressure of gas in both bulbs P1=P2=76cm of Hg=0.76m of Hg


Temperature of bulb placed in ice T2=0=273.15K


Temperature of other bulb T’2=62=335.15K


Let each of the bulbs have n1 moles initially.


Now since the second bulb has kept at higher temperature gas in second bulb will expand and some of the gas will flow to first bulb and number of moles will change in second bulb.


Let the number of moles in second bulb after its pressure reached P be n2.


Volume of both the bulbs is same so V1=V2=V.


Applying ideal gas equation in both bulbs


PV=nRT


Where V= volume of gas


R=gas constant =8.3JK-1mol-1


T=temperature


n=number of moles of gas


P=pressure of gas.


and equating the value of constant R





Number of moles left out of second bulb after temperature rose=n1-n2



Let n3 moles be left when pressure reached P in fist bulb. Applying ideal gas equation in first bulb, before and after temperature change.





Also,


=own moles of first bulb n1+moles received from second bulb


=n1+n1-n2


Substituting the value of n3 and n2 in above equation



Taking n1 common





P=0.8375m of Hg


The new value of the pressure inside the bulbs is 83.75cm of Hg.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Pure water HC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Find the number oHC Verma - Concepts of Physics Part 2

Consider a gas ofHC Verma - Concepts of Physics Part 2