(a) Electronic configuration of A = 2, 8, 2
Electronic configuration of B = 2, 8, 3
(b) Along a period the atomic size of elements decreases. Thus element A has a higher size than B.
(c) Along a period due to increase in effective nuclear charge the tendency to loss electrons decreases, thus A has more metallic character.
(d) Valency of an O atom is -2. Hence formula is A2 O2
Valance electrons B atom is 3. Hence formula is B2O3
(e) Along a period the metallic character of elements decreases. A is thus more metallic.
(f) Valency of a Cl atom is -1.
Number of valance electrons in A=2 hence ACI2
Number of valance electrons in B=2 hence BCI3
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