Q. 63.5( 10 Votes )

# Two electri

Answer :

Let

Resistance, power and current of bulb P = RP, PP, IP

Resistance, power and current of bulb Q = RQ ,PQ, IQ

It is given in question that, We know that power dissipated across any resistance is given as

P = I2R

Where P = power dissipated

I = current through the resistance

According to question both the resistance is in series. Therefore, current through both the resistance will be same.

IP = IQ …..(ii) From equation(ii), From equation (i), the ratio of power dissipation in bulbs P and Q is 1:2.

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