Q. 23.5( 10 Votes )

Two cells of 3V each are connected in parallel. An external resistance of 0.5 Ω is connected is series to the junction of two parallel resistors of 4 Ω and 2Ω and then to common terminal of battery through each resistor as shown in figure. What is the current flowing through 4Ω resistor?


A. 0.25 A

B. 0.55A

C. 0.35 A

D. 1.50A

Answer :


The given circuit can be reduced to : -


The equivalent resistance can be calculated as: -



Req= + 0.5 =


Req =


The net current in the circuit is given as



= A, so,


Inet = 18/11 A.


The circuit can be drawn as shown aside,


The voltage drop across the parallel resistance combination is , so net current in the 4 Ω resistor is = 0.55 A .

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