Answer :

Given,


Capacitance are 4.0 μF C1) and 6.0 μF C2)


The voltage of battery, V is 20V


Formula used


Let us represent the arrangement as



In a series arrangement the the charge on both the capacitance are same, and can be found out by the equation,



Where Q and V represents the Charge and Potential difference respectively.


in series arrangement with Capacitance C1 and C2, Ceff can be found out as,



Or,



The energy stored in the capacitor,E in Jules) can be found out by the relation,



Where C is the capacitance of the capacitor in Farad and V is the potential difference across the capacitor.


We have to find the equivalent capacitance by eqn.2


So,



Or,



Now the energy supplied by the battery is equivalent to the energy stored in the equivalent capacitor with capacitance Ceff. Hence by eqn.3, we get



Or,



The supplied energy will be twice of the stored energy, since half of the supplied energy will be dissipated by the resistance of the circuit.


Hence the supplied energy will be



Hence an amount of 960 μJ will be supplied by the battery.


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