Answer :

Two capacitance each having capacitance C and breakdown voltage V joined in series.

The general formula for effective capacitance of a series combination of n capacitors is given by

The equivalent capacitance of two capacitors in series is given by

Where

C_{1} is the capacitance of the first capacitor

C_{2} is the capacitance of the second capacitor

On Solving for C, we get

Since, C_{1}=C_{2}=C

Putting the values of C_{1} and C_{2}, we get

Also, Capacitors in series have same amount of charge

∴ Q_{1}=Q_{2}=Q

Therefore, potential difference across both the capacitors are also equal to V

So, the voltage across the system is the sum of voltage across each capacitor.

Therefore, **the breakdown voltage of the combination =V+V****⇒** **2V**

**Thus, the capacitance and breakdown voltage of the combination is C/2 and 2V respectively**

Rate this question :

In the circuit shPhysics - Exemplar

A cylindrical capHC Verma - Concepts of Physics Part 2

In the circuit shPhysics - Exemplar

A capacitor is maHC Verma - Concepts of Physics Part 2

Find the equivaleHC Verma - Concepts of Physics Part 2

A finite ladder iHC Verma - Concepts of Physics Part 2

Find the capacitaHC Verma - Concepts of Physics Part 2

If the capacitorsHC Verma - Concepts of Physics Part 2

The equivalent caHC Verma - Concepts of Physics Part 2

Both the capacitoHC Verma - Concepts of Physics Part 2