# Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will beA. 2C and 2VB. C/2 and V/2C. 2C and V/2D. C/2 and 2V

Two capacitance each having capacitance C and breakdown voltage V joined in series.

The general formula for effective capacitance of a series combination of n capacitors is given by

The equivalent capacitance of two capacitors in series is given by

Where

C1 is the capacitance of the first capacitor

C2 is the capacitance of the second capacitor

On Solving for C, we get

Since, C1=C2=C

Putting the values of C1 and C2, we get

Also, Capacitors in series have same amount of charge

Q1=Q2=Q

Therefore, potential difference across both the capacitors are also equal to V

So, the voltage across the system is the sum of voltage across each capacitor.

Therefore, the breakdown voltage of the combination =V+V 2V

Thus, the capacitance and breakdown voltage of the combination is C/2 and 2V respectively

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RELATED QUESTIONS :

In the circuit shown in Fig. 2.4. initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important).

[Take Q1’ and Q2’ as charges on C1 and C2 and V1 and V2 as voltage respectively.]

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