Q. 23.7( 3 Votes )

Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be
A. 2C and 2V

B. C/2 and V/2

C. 2C and V/2

D. C/2 and 2V

Answer :

Two capacitance each having capacitance C and breakdown voltage V joined in series.


The general formula for effective capacitance of a series combination of n capacitors is given by



The equivalent capacitance of two capacitors in series is given by



Where


C1 is the capacitance of the first capacitor


C2 is the capacitance of the second capacitor


On Solving for C, we get



Since, C1=C2=C


Putting the values of C1 and C2, we get



Also, Capacitors in series have same amount of charge


Q1=Q2=Q


Therefore, potential difference across both the capacitors are also equal to V


So, the voltage across the system is the sum of voltage across each capacitor.


Therefore, the breakdown voltage of the combination =V+V 2V


Thus, the capacitance and breakdown voltage of the combination is C/2 and 2V respectively

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RELATED QUESTIONS :

In the circuit shown in Fig. 2.4. initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important).

[Take Q1’ and Q2’ as charges on C1 and C2 and V1 and V2 as voltage respectively.]



Then


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