Answer :

The momentum of the ball can be calculated as

p = m× v

Where,

‘m’ is the mass of the ball

‘v’ is the velocity of the ball.

Given,

Mass of each billiard ball, m = 0.05 kg

Initial velocity of each ball, u = 6 m/s

The initial momentum, p_{i}, of each ball is

P_{i} = m× u= 0.05 kg × 6 m/s

⇒ p_{i} = 0.3 kg m/s

The balls rebound after the collision thus, they change directions but the magnitude of the velocity remains the same,

Now,

Final velocity of each ball, v = -6 m/s

The final momentum, p_{f} of each ball is,

p_{f}= m× v = 0.05 kg × -6 m/s

⇒ p_{f} = -0.3 kg m/s

Impulse imparted to each ball, ‘I’ = change in the momentum of the system

⇒ I= p_{f} - p_{i} = (-0.3 – 0.3) kg m/s

⇒ I= -0.6 kg m/s

The negative sign is because the impulse imparted to each of the balls are in opposite directions.

the impulse imparted to each ball due to the other is 0.6 N in opposite directions.

Rate this question :

The position timePhysics - Exemplar

Two billiard ballPhysics - Exemplar

Two particles of HC Verma - Concepts of Physics Part 1

Why are porcelainPhysics - Exemplar

A uniform square HC Verma - Concepts of Physics Part 1

In the previous pPhysics - Exemplar

In <span lang="ENPhysics - Exemplar