Q. 124.3( 8 Votes )

Three resistors are connected as shown in the figure. Through the resistor 5 ohms, a constant current of 1 ampere is flowing.



a. What is the current through the other two resistors?

b. What is the potential difference across AB and across AC?

c. What is the total resistance?

Answer :

a. V across point BC = ?


I = 1 A


Rp = 6 ohm [derived in c. below]


So V = IR


= 6A × 1Ω


V = 6 ohm


I1 =


I1 =


I1 = 0.6 A


Similarly I2 =


I2 =


I2 = 0.4 A


b. I = 1 A


R = 5 ohm


So V across AB = ?


We know V = IR


V = 5A × 1Ω


V = 5 V


V across AC = ?


Total R = 11 ohm [derive in c. below]


V = 1 × 11


V = 11 V


c. Total resistance = ?


Resistors R1 and R2 are in parallel


So





Rp = 6 ohm


Total R = 5 ohm + 6 ohm


R = 11 ohm


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