Power dissipated by the resistor of 2 ohm (P) = i2R (where i is the current through the resistor and R is the resistance of the resistor.)
Therefore: i2 = P/R =(18/2) A = 9A
⇒ i= 3A
Resistances B and C are connected in parallel, therefore, the current is equally divided in between them i.e. 1.5A.
The effective resistance across the resistors of 4 ohm connected in parallel is:
The resistance is equal hence same current will flow through these. Hence the potential difference across the parallel combination and the 2Ω resistor is the same.
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