Answer :

Power dissipated by the resistor of 2 ohm (P) = i^{2}R (where i is the current through the resistor and R is the resistance of the resistor.)

Therefore: i^{2} = P/R =(18/2) A = 9A

⇒ i= 3A

Resistances B and C are connected in parallel, therefore, the current is equally divided in between them i.e. **1.5A**.

**OR**

The effective resistance across the resistors of 4 ohm connected in parallel is:

R_{eq}=

The resistance is equal hence same current will flow through these. Hence the potential difference across the parallel combination and the 2Ω resistor is the same.

Rate this question :

Power of a lamp iAll In One Science

Show how would yoScience - Board Papers

Three 2Ω resistorXam idea - Science

The electric poweTogether With Science

An electric lamp Together With Science