There capacitors A. 6 μF, 18 μF

B. 3 μF, 12 μF

C. 2 μF, 12 μF

D. 2 μF, 18 μF

Given:

Three capacitors of capacitances 6μF each

i)The minimum capacitance can be obtained by connecting all three capacitors in series.

In series combination, charges on the two plates are same on each capacitor.

The general formula for effective capacitance of a series combination of n capacitors is given by

The equivalent capacitance in this case is given by

⇒

ii) The maximum capacitance can be obtained by connecting all three capacitors in parallel.

In this case, the same potential difference is applied across all capacitors.

The general formula for effective capacitance Ceq for parallel combination of n capacitors is given by

The equivalent capacitance in this case is given by

⇒ C_eq=3C

C_eq=3× 6=18μF

Therefore, the maximum and minimum capacitance that can be obtained is 18μF and 2μF respectively.