Q. 294.4( 5 Votes )
The work function
Wavelength of radiation from laser = 3300 Å = 3300 × 10-10m
Energy radiated by the laser, E is given by,
E = Energy of photon
h = Planck’s constant = 6.6 × 10-34 Js
c = 3 × 108 ms-1
λ = wavelength of photon
putting values in equation (1) we get,
E = 6 × 10-19 J
E = (6/1.6) × 10-19
E = 3.158 eV
We observe that Na and K have work functions less than the energy radiated by the laser so photoelectric effect will take place in case of them, whereas no photo-electric effect will occur in case of Mo and Ni.
Even if the laser is brought closer, it will have no effect on the outcome as the photo-electric effect is independent of the intensity of light.
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