# The work function

Given:

Wavelength of radiation from laser = 3300 Å = 3300 × 10-10m

Energy radiated by the laser, E is given by,

…(1)

Where,

E = Energy of photon

h = Planck’s constant = 6.6 × 10-34 Js

c = 3 × 108 ms-1

λ = wavelength of photon

putting values in equation (1) we get,

E = 6 × 10-19 J

E = (6/1.6) × 10-19

E = 3.158 eV

We observe that Na and K have work functions less than the energy radiated by the laser so photoelectric effect will take place in case of them, whereas no photo-electric effect will occur in case of Mo and Ni.

Even if the laser is brought closer, it will have no effect on the outcome as the photo-electric effect is independent of the intensity of light.

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