Answer :

Given:



Wavelength of radiation from laser = 3300 Å = 3300 × 10-10m


Energy radiated by the laser, E is given by,


…(1)


Where,


E = Energy of photon


h = Planck’s constant = 6.6 × 10-34 Js


c = 3 × 108 ms-1


λ = wavelength of photon


putting values in equation (1) we get,



E = 6 × 10-19 J


E = (6/1.6) × 10-19


E = 3.158 eV


We observe that Na and K have work functions less than the energy radiated by the laser so photoelectric effect will take place in case of them, whereas no photo-electric effect will occur in case of Mo and Ni.


Even if the laser is brought closer, it will have no effect on the outcome as the photo-electric effect is independent of the intensity of light.


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