Answer :

For photoemission energy ‘E’ of incident radiation must be more than or equal to work function ‘ϕ0’ of the metal.


E ϕ0 (The Condition for photoelectric emission)


E = hv = hc/λ


Where h = plank’s constant = 6.63 × 10-34 J. sec


ν = frequency of radiation


c = speed of light = 3 × 108 m/s


λ = wavelength of radiation


E = 6.63 × 10-34 × 3 × 108 / 330 × 10-9


= 6.018 × 10-19 J = 6.018 × 10-19/1.6 × 10-19 eV


= 3.76 eV


ϕ0 = 4.2 eV as per question.


E < ϕ0, therefore photoemission will not take place.


No photoemission will take place as work function is more than the photon energy of the incident radiation.


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