Let λ be the wavelength of the photon. The wavelength of De-Broglie’s wavelength is given by,
Where, m = mass of electron
v = velocity
The kinetic energy of the electron is given by,
Photon has energy as,
Taking ration of kinetic energy and energy we get,
Thus, the energy of a photon is (2lmc/h) times the kinetic energy of electron.
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