The vapour pressu

Given: 1 molal solution means 1 mole of solute present in 1000g of water solvent)

Molecular weight of water = H2O = 1 × 2 + 16 = 18g/mol

No. of moles of water, n = given mass /molecular weight

n = 1000/18 = 55.56 gmol-1

Mole fraction of solute in solution,x2 = moles of solute/(moles of solute + moles of water)

x2 = 1/(1 + 55.56)

x2 = 0.0177

Given vapour pressure of pure water at 300k is 12.3 kpa

Apply the formula:

P1 = 12.0823kpa

which is the vapour pressure of the solution.

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