The value of <spa

Given:

The reaction is 3O₂ (g) ⇌ 2O₃ (g)

The equilibrium constant of the given reaction = 2.0×10^–50

Temperature = 25° C

Equilibrium concentration of O₂ ([O₂]) = 1.6 ×10^–2 M

To find out the equilibrium concentration of O₃, we will apply the

Law of Chemical Equilibrium, i.e., K_c =

Where X and Y are the products and A and B are the reactants.

Hence, equilibrium constant (K_c) of the given reaction,

3O₂ (g) ⇌ 2O₃ (g)

K_c =

As K_c = 2.0×10^–50 (given) and [O₂] = 1.6 ×10^–2 M (given)

∴ 2.0×10^–50 =

⇒[O₃]² = 2.0×10^–50 × (1.6 × 10^-2 M)³

⇒[O₃]² = 8.192 × 10^-56

⇒[O₃] =

⇒[O₃] = 2.86 × 10^-28 M

Thus, the equilibrium concentration of O₃ is 2.86 × 10^-28M