Answer :

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Mass of the heavier block, m1 = 3 kg


Mass of the lighter block, m2 = 2 kg


Let the tension in the string be T and acceleration in the system be a.


According to the diagram,


T = m1a + m1g T = 2(g+a)


m2g = T + m2a T = 3(g-a)


a= g/5 m/s2


We need to find work done by gravity in the fourth second.


Time, t = 4 s


Change in height, h = 1/2 a(2t-1) (From equations of motion)



Work done by gravity = (m2-m1)×g×h


= (3-2) × 9.8 × 6.86


= 67.228 N


≈ 67 N


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