Q. 134.5( 2 Votes )

The thermal decom

Answer :

We know, for first order kinetics,


k =


where, k = rate constant.


t = time taken.


a =initial concentration.


a-x = concentration left after t amount of time.


Now, k=2.4 x 10-3 s-1 as given in the question.


Now, we have to find out the time taken for the decomposition of three-fourths of the compound.


Decomposed part(x) = 0.75a


2.4 x 10-3=


t =


= = 577.6sec. [If, log x = a, then log () = -a]


So, it will it take 577.6 sec for three- fourths of initial quantity of HCO2H to decompose.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USChemistry - Board Papers

Why can’t moleculChemistry - Exemplar

Note: In the follChemistry - Exemplar

Note: In the follChemistry - Exemplar

Match the items oChemistry - Exemplar

How are most probChemistry - Exemplar