Answer :

Given:


Temp of A=12° c


Temp of B=19° c


Temp of C=28° c


Formula used:


ΔQ=MCΔT


ΔQ=heat exchange


ΔT=tempeature change


M=mass


C=heat capacity


Now;


When A and B are mixed


MA(16-12)=MB(19-16)


MB=4MA/3


Also;


When B and C are mixed


MB(23-19)=Mc(28-23)


MB=5Mc/4


So when A and C are mixed let the final temperature be T


MA(T-12)=Mc(28-T)


MB(T-12)=MB(28-T)


15T-180=448-16T


T=20.3° C


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