Q. 615.0( 1 Vote )
Volume of room= 50m3
Mass of water=500g
Molar mass of H2O M=2+16=18g
Saturation vapor pressure(SVP) at 300 K = 3.3 kPa=3300Pa
Let vapor pressure inside the room be P1
Since the floor has dried that means water on the floor has been evaporated.
Let P2 be the partial pressure of evaporated water
We know ideal gas equation
Where V= volume of gas
R=gas constant =8.3JK-1mol-1
n=number of moles of gas
P=pressure of gas.
And Number of moles n=
Total pressure of room= partial pressure of evaporated water+ pressure of air inside the room
The relative humidity when the floor dries is 61.9%.
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