Answer :

Given


Temperature T=300K


Relative humidity=20%


Volume of room= 50m3


Mass of water=500g


Molar mass of H2O M=2+16=18g


Saturation vapor pressure(SVP) at 300 K = 3.3 kPa=3300Pa


Let vapor pressure inside the room be P1




P1=0.23.3103=660Pa


Since the floor has dried that means water on the floor has been evaporated.


Let P2 be the partial pressure of evaporated water


We know ideal gas equation


PV=nRT


Where V= volume of gas


R=gas constant =8.3JK-1mol-1


T=temperature


n=number of moles of gas


P=pressure of gas.


And Number of moles n=




P2=1385Pa


Total pressure of room= partial pressure of evaporated water+ pressure of air inside the room


P=P2+P1


P=1385+660=2045Pa



The relative humidity when the floor dries is 61.9%.


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