The temperature a

We know ideal gas equation

PV=nRT

Where V= volume of gas

R=gas constant

T=temperature

n=number of moles of gas

P=pressure of gas

Number of moles n ==

Density

Given:

Temperature of Shimla T₁=15.0°C

T(K)=T ()+273.15

T₁=T(K)=15+273.15=288.15K

Pressure of Shimla P₁ = 72.0 cm of mercury

Temperature of Kalka T₂ = 35.0°C

T(K)=T ()+273.15

T₂=T(K)=35+273.15=308.15K

Pressure of Kalka P₂=76.0 cm of mercury

Substituting the value of n and in ideal gas equation, we get

=

So,

Taking the ratio of equations (i) and (ii),

The ratio of air density at Kalka to the air density at Shimla is 0.98.