Answer :

When the switch is closed and the circuit is in steady state, no current passes through the capacitor.

Applying Kirchhoff’s loop rule on loop bedcb,

Substitute I1 = 0 as there is no current through the capacitor at steady state.

Now, as they are in parallel

Note that Vaf is the potential difference across the capacitor.

When the switch is just opened, the potential difference across it is the same for a moment as the charge and capacitance is the same. However, the charge and potential decrease slowly as the capacitor starts discharging.


We know that when discharging,

Applying Kirchhoff’s loop rule on fabef,

At , and

Here, R = 10Ω and C = 25μF


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