Q. 54.0( 2 Votes )

The separation be A. Charge on the capacitor

B. Potential difference across the capacitor

C. Energy of the capacitor

D. Energy density between the plates.

Answer :

When we increase the separation between the plates of a charged parallel capacitor the value of Capacitance decreases by the formula


Where,


d=separation between the plates


A=area of plates


ϵ0=absolute permittivity of vacuum


Charge on the capacitor remains unchanged because no charge transfer takes place.


Potential difference across the capacitor changes by the formula



Where,


Q= charge on the capacitor


C=capacitance


Similarly Energy across the capacitor given by



Where,


C=capacitance


V=potential difference across capacitor


So, as V changes energy stored also changes


Therefore, on increasing separation between the plates of capacitor, potential difference and energy of capacitor changes whereas charge and energy density remains the same.

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