Q. 54.0( 2 Votes )
The separation be A. Charge on the capacitor
B. Potential difference across the capacitor
C. Energy of the capacitor
D. Energy density between the plates.
When we increase the separation between the plates of a charged parallel capacitor the value of Capacitance decreases by the formula
d=separation between the plates
A=area of plates
ϵ0=absolute permittivity of vacuum
Charge on the capacitor remains unchanged because no charge transfer takes place.
∴ Potential difference across the capacitor changes by the formula
Q= charge on the capacitor
Similarly Energy across the capacitor given by
V=potential difference across capacitor
So, as V changes energy stored also changes
Therefore, on increasing separation between the plates of capacitor, potential difference and energy of capacitor changes whereas charge and energy density remains the same.
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