# The rms speed of

Root mean square velocity of gas is given as

vrms

where R=gas constant whose value is 8.31 J/mol K.

T=temperature of gas.

M= molar mass of molecule of gas

Given,

Root mean square of oxygen

vrms

Molar mass of oxygen molecule M=32. So,

When temperature is doubled, oxygen molecule dissociates into oxygen atom.

Molar mass of oxygen atom M’=16

New temperature T’=2T

Then rms speed of oxygen atom becomes

Multiplying and diving above equation by 2 we get,

New rms speed of oxygen will ve 2v.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Pure water HC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

<span lang="EN-USHC Verma - Concepts of Physics Part 2

Find the number oHC Verma - Concepts of Physics Part 2

Consider a gas ofHC Verma - Concepts of Physics Part 2