Q. 11

The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become
A. v

B. v√2

C. 2v

D. 4v.

Answer :

Root mean square velocity of gas is given as


vrms


where R=gas constant whose value is 8.31 J/mol K.


T=temperature of gas.


M= molar mass of molecule of gas


Given,


Root mean square of oxygen


vrms


Molar mass of oxygen molecule M=32. So,



When temperature is doubled, oxygen molecule dissociates into oxygen atom.


Molar mass of oxygen atom M’=16


New temperature T’=2T


Then rms speed of oxygen atom becomes



Multiplying and diving above equation by 2 we get,




New rms speed of oxygen will ve 2v.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Rotational Kinetic Energy43 mins
Colligative Properties {Theory}34 mins
Electric Flux - Theory46 mins
Wheatstone Bridge - Theory Class35 mins
Arrhenius equation & Collision Theory59 mins
Superfast Revision of Potential & Potenial Energy (Theory + Interactive Quiz)47 mins
Microsporogenesis & Megasporogenesis49 mins
DNA Fingerprinting42 mins
NEET 2021 | Transcription - An important Topic62 mins
Meselson and Stahl experiment49 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :