Q. 385.0( 1 Vote )

# The pulley shown in figure (10-E8) has a radius 10 cm and moment of inertia 0.5 kg-m2 about its axis. Assuming the inclined planes to be frictionless, calculate the acceleration of the 4.0 kg block. The acceleration of the 4kg block is given as Given

The radius of the pulley is given as 10 cm, the inertia 0.5 and the mass of the blocks are given as 2 kg and 4 kg.

Formula Used

The formula used to find the acceleration of the mass pulled/pushed is determined by the second law of Newton when the Force/Tension applied is equivalent to the product of mass and acceleration where is the force of the mass in terms of tension, is the acceleration and m is the mass of the block.

Explanation

The mass and tension relationship of the 4 kg block is given as The tension and the mass of the 4 kg block is denoted as and respectively.

The mass and tension relationship of the 2 kg block is given as The tension and the mass of the 2 kg block is denoted as and respectively.

The difference in their tension is given in terms of moment of Inertia Adding all the three equations we get the value of the acceleration of the blocks made the 4 kg block is Putting the values of the masses, radius and gravity as , we get the value of acceleration as  Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Revise Full Mechanics in One Shot63 mins  A Lecture on Head-on Collision49 mins  Pseudo Force52 mins  Tips &Tricks in Rotational Motion52 mins  Elaborative Lecture on Constraint Motion59 mins  Questions based on rotational motion44 mins  Inelastic collisions in 1 D44 mins  Interactive Quiz on Rotational Motion66 mins  Elasticity52 mins  Moment of Inertia | Understanding the basics51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 