# The pressure p and volume V of an ideal gas both increase in a process.A. Such a process is not possible.B. The work done by the system is positive.C. The temperature of the system must increase.D. Heat supplied to the gas is equal to the change in internal energy.

We know that,

Work done = force ×displacement

Volume = area ×displacement

Therefore,

Work done=pressure ×volume

Let change in the volume of system = ΔV = V2-V1

Pressure =P

Thus, work done by the system W

ΔW=PΔV

It is given that volume in increasing i.e. ΔV>0. So, ΔW>0 and positive.

From ideal gas equation, we know that

PV=nRT

Where P=pressure

V=volume

n=number of moles

R=gas constant

T=temperature

So, if both pressure and volume are increasing, then

the temperature must also increase as n and R are constant.

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