Answer :

Given:

Potential energy (P.E.) =

Let,

X component of force = F_{X}

Y component of force = F_{Y}

Let, net force

If, θ = angle that makes with the horizontal

Then,

Displacement of the particle is along a straight line path having, slope

Let, the equation of straight line be

Where,

m = slope

c = intercept

So,

This line passes through (6, 4)

So,

If the path passes through y-axis at (0, y_{0})

Then,

So the path crosses y-axis at (0, –4)

Displacement between (6, 4) and (0, –4) = s

u = 0

a = 5 ms^{–2}

s = 10 m

The speed at which particle crosses x is =

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