Answer :


Total energy of the particle, E = 1 J

Force constant, k = 0.5 N m-1

The total energy is equal to the sum of kinetic energy and potential energy.

So, E = PE + K

E = kx2 + mv2

So, 1 = kx2 + mv2

When the velocity of the particle is zero i.e., at the turning point, the kinetic energy is zero.

1 = kx2

x2 = 2/k

x2 = 2/0.5

x2 = 4

x = �2

Hence, the particle turns back at x= �2.

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