The potential dif

0.6Ω

Given,

The potential difference across the setup, V= 7.2V

The emf of the cell, E=6V

The current flowing through the circuit, i= 2A

Formula used:

When the battery is charging the potential difference, V across the cell can be written as,

Where ‘E’ is the emf of the cell and ‘r’ is internal resistance of the cell.

Solution:

As the battery is getting charged, the internal resistance can be calculated from the eqn.1, as

And by substituting the given values,

Hence the internal resistance of the cell is 0.6Ω

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