Answer :

0.6Ω

Given,


The potential difference across the setup, V= 7.2V


The emf of the cell, E=6V


The current flowing through the circuit, i= 2A


Formula used:


When the battery is charging the potential difference, V across the cell can be written as,



Where ‘E’ is the emf of the cell and ‘r’ is internal resistance of the cell.


Solution:


As the battery is getting charged, the internal resistance can be calculated from the eqn.1, as



And by substituting the given values,



Hence the internal resistance of the cell is 0.6Ω


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