Answer :



The potential difference across the setup, V= 7.2V

The emf of the cell, E=6V

The current flowing through the circuit, i= 2A

Formula used:

When the battery is charging the potential difference, V across the cell can be written as,

Where ‘E’ is the emf of the cell and ‘r’ is internal resistance of the cell.


As the battery is getting charged, the internal resistance can be calculated from the eqn.1, as

And by substituting the given values,

Hence the internal resistance of the cell is 0.6Ω

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