Q. 4

# The plates of a p

Given:

Two plates of a parallel plate capacitor with equal charge.

Here, both the plates are given same charge +Q.

Consider q charge on face II so that induced charge on face III is -q

Assume a rectangular Gaussian surface ABCD having area, A as shown in the above fig.

Thus, Electric field at point P due to face I E1=

Electric field at point P due to face II E2=

Electric field at point P due to face III E3=

Electric field at point P due to face IV E4=

negative sign because electric field due to face IV is in leftwards direction).

Since , point P lies inside the conductor thee total electric field at P must be zero

E1+E2+E3+E4=0

=0

q=0

Therefore zero charge appears on face II and III and Q charge appears on face I and IV

Potential difference b/w the plates is given by

V=0 both the plates are at same potential since both are given equal charges)

1)Potential difference between the plates=0.

2)Charges on outer faces of plates=+Q.

3)Charges on inner faces of plates=0.

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