Answer :


Given:


Two plates of a parallel plate capacitor with equal charge.


Here, both the plates are given same charge +Q.



Consider q charge on face II so that induced charge on face III is -q


Assume a rectangular Gaussian surface ABCD having area, A as shown in the above fig.


Thus, Electric field at point P due to face I E1=


Electric field at point P due to face II E2=


Electric field at point P due to face III E3=


Electric field at point P due to face IV E4=


negative sign because electric field due to face IV is in leftwards direction).


Since , point P lies inside the conductor thee total electric field at P must be zero


E1+E2+E3+E4=0


=0


q=0


Therefore zero charge appears on face II and III and Q charge appears on face I and IV


Potential difference b/w the plates is given by



V=0 both the plates are at same potential since both are given equal charges)


1)Potential difference between the plates=0.


2)Charges on outer faces of plates=+Q.


3)Charges on inner faces of plates=0.


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