Two plates of a parallel plate capacitor with equal charge.
Here, both the plates are given same charge +Q.
Consider q charge on face II so that induced charge on face III is -q
Assume a rectangular Gaussian surface ABCD having area, A as shown in the above fig.
Thus, Electric field at point P due to face I E1=
Electric field at point P due to face II E2=
Electric field at point P due to face III E3=
Electric field at point P due to face IV E4=
negative sign because electric field due to face IV is in leftwards direction).
Since , point P lies inside the conductor thee total electric field at P must be zero
Therefore zero charge appears on face II and III and Q charge appears on face I and IV
Potential difference b/w the plates is given by
∴ V=0 both the plates are at same potential since both are given equal charges)
1)Potential difference between the plates=0.
2)Charges on outer faces of plates=+Q.
3)Charges on inner faces of plates=0.
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