Q. 495.0( 1 Vote )

# The perpendicular from the origin to the line y = mx+c meets it at the point (-1,2). Find the values of m and c.

Now(-1,2) lies on y=mx+c

2 = -m+c

m-c = -2

Slope of the perpendicular =

Therefore the slope of the required line perpendicular the line from the origin m =

Substituting in the equation m-c = -2

-c=-2

c=

m=, c=

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