Answer :

Given:


Frequency of the wave = 256 Hz


Velocity of the wave = 360ms-1


(a) In the second instant, all the points of the wave are at the mean position. The time taken to reach the mean position from the amplitude is therefore the time at which the second curve is plotted. The distance to reach the mean position from the amplitude is distance between a node and an antinode that equals one-fourth the wavelength. The wavelength therefore is given by,



where v is the velocity and f is the frequency of the wave.



And



Therefore time taken to reach mean position,



Therefore, the second curve was plotted at time of t = 9.72 x 10-4 s.


(b) Nodes are points that undergo the minimum displacement and antinodes are points that undergo the maximum displacement. Thus, the points A, B, C, D, E, are the node and the points A’ and C’ are the antinodes.


(c) A’ and C’ are successive antinodes, and the distance between two successive antinodes is the wavelength of the wave, therefore



Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The earth has a rPhysics - Exemplar

If c is r.m.s. spPhysics - Exemplar

A steel wire has Physics - Exemplar

The pattern of stPhysics - Exemplar

Speed of sound waPhysics - Exemplar

A train, standingPhysics - Exemplar

A sound wave is pPhysics - Exemplar

A steel wire of mHC Verma - Concepts of Physics Part 1

Two wires are kepHC Verma - Concepts of Physics Part 1

With propagation Physics - Exemplar