Q. 133.8( 46 Votes )
The partial pressure of ethane over a solution containing 6.56 × 10–3 g of ethane is 1 bar. If the solution contains 5.00 × 10–2 g of ethane, then what shall be the partial pressure of the gas?
Mass of ethane in solution A = 6.56 × 10–3 g
Partial pressure of solution A = 1 bar
Mass of ethane in solution B = 5.00 × 10–2 g
To find: Partial Pressure of gas
By Henry’s law:
Mass of dissolved gas M = k × P
k = proportionality constant
P = Partial Pressure
⇒ M1 = k × P1 ……………… 
⇒ M2 = k × P2 …………….. 
Dividing the  by , we get
P2 = 7.62 bar
Therefore the partial pressure of the gas is 7.62 bar.
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