# The outer cylinders of two cylindrical capacitors of capacitance 2.2 μf each are kept in contact, and the inner cylinders are connected through a wire. A battery of emf 10V is connected as shown in the figure. Find the total charge supplied by the battery to the inner cylinders. Lets take inner cylinders as A and B. and outer cylinders as A1 and B1. Inner cylinders A and B are connected through a wire. Outer cylinders kept in contact. If we draw the diagram, it will be look like as fig. Given

capacitance C= 2.2μF

Voltage=10V

Capacitors are kept in parallel. So the potential difference across them is the same.

Formula used:

The magnitude of the charge on each capacitor is Where

Q is the charge of the capacitor

C is the Capacitance of the capacitor

V is the voltage across the capacitor Inner cylinders of the capacitor are connected to the positive terminal of the battery. So the charge on each of them is +22μC

Net charge on the inner cylinders is = 22μC+22μC= +44μC

Note: If it is asked for a charge on outer cylinders of the capacitor. A net charge will be equal to -44μC because they are connected to the negative terminal of the battery).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Combination of capacitorsFREE Class  Interactive Quiz on Combination of capacitorsFREE Class  How does combination of capacitors work?34 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

In the circuit shown in Fig. 2.4. initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important).

[Take Q1’ and Q2’ as charges on C1 and C2 and V1 and V2 as voltage respectively.] Then

Physics - Exemplar