Answer :

Lets take inner cylinders as A and B. and outer cylinders as A1 and B1. Inner cylinders A and B are connected through a wire. Outer cylinders kept in contact. If we draw the diagram, it will be look like as fig.



Given


capacitance C= 2.2μF


Voltage=10V


Capacitors are kept in parallel. So the potential difference across them is the same.


Formula used:


The magnitude of the charge on each capacitor is



Where


Q is the charge of the capacitor


C is the Capacitance of the capacitor


V is the voltage across the capacitor



Inner cylinders of the capacitor are connected to the positive terminal of the battery. So the charge on each of them is +22μC


Net charge on the inner cylinders is = 22μC+22μC= +44μC


Note: If it is asked for a charge on outer cylinders of the capacitor. A net charge will be equal to -44μC because they are connected to the negative terminal of the battery).


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