Q. 114.8( 4 Votes )

The outer cylinders of two cylindrical capacitors of capacitance 2.2 μf each are kept in contact, and the inner cylinders are connected through a wire. A battery of emf 10V is connected as shown in the figure. Find the total charge supplied by the battery to the inner cylinders.

Answer :

Lets take inner cylinders as A and B. and outer cylinders as A1 and B1. Inner cylinders A and B are connected through a wire. Outer cylinders kept in contact. If we draw the diagram, it will be look like as fig.


capacitance C= 2.2μF


Capacitors are kept in parallel. So the potential difference across them is the same.

Formula used:

The magnitude of the charge on each capacitor is


Q is the charge of the capacitor

C is the Capacitance of the capacitor

V is the voltage across the capacitor

Inner cylinders of the capacitor are connected to the positive terminal of the battery. So the charge on each of them is +22μC

Net charge on the inner cylinders is = 22μC+22μC= +44μC

Note: If it is asked for a charge on outer cylinders of the capacitor. A net charge will be equal to -44μC because they are connected to the negative terminal of the battery).

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In the circuit shown in Fig. 2.4. initially key K1 is closed and key K2 is open. Then K1 is opened and K2 is closed (order is important).

[Take Q1’ and Q2’ as charges on C1 and C2 and V1 and V2 as voltage respectively.]


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