Q. 134.3( 35 Votes )

The number densit

Answer :

Number density of free electrons in a copper conductor, n = 8.5 × 1028 per meter cube

Length of Copper Wire l = 3 meter


Area of cross section of wire A = 2 × 10-6 meter square


Current drawn by wire is given 3 Ampere


Since I = nAeVd


Here Vd is the drift velocity and “e” is the electron charge 1.6 × 10-19 Coulomb


And Vd Drift velocity is


Therefore


I = nAel/t


Or t = nAel/I



t = 2.7 × 104 second


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