Q. 425.0( 1 Vote )

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Answer :

o The enthalpy change of the given reaction can be calculated from the relation: Σbond enthalpy of reactants- Σbond enthalpy of products

For the reaction

H2(g) + Br2(g) 2HBr(g)

Enthalpy change

= (Bond energy of H-H bond + Br-Br bond) – (2 × bond energy of H-Br)

= (435 + 192) kJ mol–1 – (2 × 368) kJ mol–1

= -109 kJ mol–1

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